5y+2[3(1-y)-2(1+y)]=22

Solution for 5y+2[3(1-y)-2(1+y)]=22 equation:

Simplifying
5y + 2[3(1 + -1y) + -2(1 + y)] = 22
5y + 2[(1 * 3 + -1y * 3) + -2(1 + y)] = 22
5y + 2[(3 + -3y) + -2(1 + y)] = 22
5y + 2[3 + -3y + (1 * -2 + y * -2)] = 22
5y + 2[3 + -3y + (-2 + -2y)] = 22

Reorder the terms:
5y + 2[3 + -2 + -3y + -2y] = 22

Combine like terms: 3 + -2 = 1
5y + 2[1 + -3y + -2y] = 22

Combine like terms: -3y + -2y = -5y
5y + 2[1 + -5y] = 22
5y + [1 * 2 + -5y * 2] = 22
5y + [2 + -10y] = 22

Reorder the terms:
2 + 5y + -10y = 22

Combine like terms: 5y + -10y = -5y
2 + -5y = 22

Solving
2 + -5y = 22

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5y = 22 + -2

Combine like terms: 2 + -2 = 0
0 + -5y = 22 + -2
-5y = 22 + -2

Combine like terms: 22 + -2 = 20
-5y = 20

Divide each side by '-5'.
y = -4

Simplifying
y = -4